Home /permanent

Trig Angle Identities

Fundamental Identity

sin⁡2a+cos⁡2a=1\sin^2a + \cos^2a = 1

Therefore:

cos⁡2a=1−sin⁡2a\cos^2a = 1 - \sin^2a

sin⁡2a=1−cos⁡2a\sin^2a = 1 - \cos^2a

Angle Sum Identity definitions

The Sine of two angles added together identity is as follows:

sin⁡(a+b)=sin⁡(a)cos⁡(b)+sin⁡(b)cos⁡(a)\sin(a + b) = \sin(a)\cos(b) + \sin(b)\cos(a)

And subtraction:

sin⁡(a−b)=sin⁡(a)cos⁡(b)−sin⁡(b)cos⁡(a)\sin(a - b) = \sin(a)\cos(b) - \sin(b)\cos(a)

The Cosine of two angles:

cos⁡(a+b)=cos⁡(a)cos⁡(b)−sin⁡(a)sin⁡(b)\cos(a + b) = \cos(a)\cos(b) - \sin(a)\sin(b)

And subtraction:

cos⁡(a−b)=cos⁡(a)cos⁡(b)+sin⁡(a)sin⁡(b)\cos(a - b) = \cos(a)\cos(b) + \sin(a)\sin(b)

Cosine Properties

Cosine is an Even Function. Meaning, any negative inputs are equal to the equivalent positive input.

cos⁡(−c)=cos⁡(c)\cos(-c) = \cos(c)

We can use the angle sum definition of a+aa + a to defined cos⁡(2a)\cos(2a):

cos⁡(2a)=cos⁡(a+a)=cos⁡(a)cos⁡(a)−sin⁡(a)sin⁡(a)=cos⁡2(a)−sin⁡2(a)\cos(2a) = \cos(a + a) = \cos(a)\cos(a) - \sin(a)\sin(a) = \cos^2(a) - \sin^2(a)

Or simply:

cos⁡(2a)=cos⁡2(a)−sin⁡2(a)\cos(2a) = \cos^2(a) - \sin^2(a)

We can express entirely in terms of cos⁡\cos Using the Fundemantla Identity:

Since we know

sin⁡2(a)=1−cos⁡2(a)\sin^2(a) = 1 - \cos^2(a)

Then

=cos⁡2(a)−(1−cos⁡2(a))= \cos^2(a) - (1 - \cos^2(a)) =cos⁡2(a)−1+cos2(a))= \cos^2(a) - 1 + cos^2(a)) =2cos⁡2(a)−1= 2\cos^2(a) - 1 =cos⁡(2a)= \cos(2a) (need to understand this part)

Cosine Reduction Identity

2cos⁡2a=cos⁡2a+12\cos^2a = \cos 2a + 1

cos⁡2a=12(1+cos⁡2a)\cos^2a = \frac{1}{2} (1 + \cos 2a)

Sine Properties

Sine is an Odd Function. Meaning, any negative inputs are equal to the negative value of the function.

sin⁡(−c)=−sin⁡(c)\sin(-c) = -\sin(c)

Sine Reduction Identity

2sin⁡2a+cos⁡2a=12\sin^2a + \cos 2a = 1 2sin⁡2a=1−cos⁡2a2\sin^2a = 1 - \cos 2a sin⁡2a=12(1−cos⁡2a)\sin^2a = \frac{1}{2} (1 - \cos 2a)